Given: Time elapsed = t = 2s, displacement = x = a √3/2, from its mean position in 2 seconds is equal to √3/2 of its amplitude. The shortest distance traveled by a particle performing S.H.M. Given: Time period = T = 2 s, Displacement x = 1/2Ī, particle passes through mean position, α = 0.Īngular velocity = ω = 2π/T = 2π/2 = π rad/s After how much time interval from t =0 will its displacement be half the amplitude? The periodic time of a body executing S.H.M. is given byĪns: Initial phase is 11☃2’ and phase of S.H.M. Given: Path length = 10 cm, amplitude = path length /2 =ġ0/2 = 5 cm, Initial displacement = x 0 = 1 cm, Displacement = x =ĭisplacement of a particle performing S.H.M. Find the epoch and the phase of motion when the displacement is 2.5 cm. The particle starts from a distance of 1 cm from the mean position towards the positive extremity. A particle performs a linear S.H.M along a path 10 cm long.
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